- The requested resource is not available tomcat 8 how to#
- The requested resource is not available tomcat 8 registration#
- The requested resource is not available tomcat 8 code#
Out.println("Unable to process try after some time") RequestDispatcher rd=req.getRequestDispatcher("registration.html") Out.println("Given details are incorrect") If(c=1||c=Statement.SUCCESS_NO_INFO & i=1||i=Statement.SUCCESS_NO_INFO) PreparedStatement ps1=con.prepareStatement(query) String query="insert into passmanager values(?,?,?,?)" PreparedStatement ps=con.prepareStatement(Query) String phone1,uname,fname,lname,dob,address,city,state,country,pin,email,password,gender,lang,qual,relegion,privacy,hobbies,fav Public void doPost(HttpServletRequest req,HttpServletResponse resp)throws ServletException,IOException Return DriverManager.getConnection(url,usname,pass) Public static Connection prepareConnection()throws ClassNotFoundException,SQLException
The requested resource is not available tomcat 8 registration#
Public class Registration extends HttpServlet I don't know what was the reason for it my Html page is I have written a Java servlet program and run it through local Tomcat 7, But it was showing following error : HTTP Status 404 - /skypark/registrationĭescription The requested resource is not available. Servlet returns “HTTP Status 404 The requested resource (/servlet) is not available” 1 answer.
The requested resource is not available tomcat 8 how to#
Instead, you should design your own user-friendly 404 error page – follow this tutorial: How to Handle Error for Java web applications.This question already has an answer here: So you need to check and use correct case for the letters in request URL.Also pay attention to the webapp name in the URL, for instance is different than TIP: in Eclipse, you can right click on the project, then click Run As > Run on Server, the IDE will always use the correct name of the web application.Finally, you should not let the user see the raw HTTP 404 error page rendered by the server. URL is case-sensitiveNote that Tomcat treats URL as case-sensitive, for instance /Register is different than /register. RequestDispatcher dispatcher = request.getRequestDispatcher(registerForm) ĭispatcher.forward(request, response) You can fix by correcting the forward path in the servlet, and make sure that the forwarded resource does actually exist in the given path.
The requested resource is not available tomcat 8 code#
Java servlet forwarding to a resource that does not existIn this case, the requested URL is handled by a Java servlet, but code in the servlet forwards to a resource (JSP, HTML…) which does not exist, as shown in the following screenshot: The code in the servlet class would look like this: String registerForm = "frontend/registerform.jsp" In older Java web application, you have to check the web deployment descriptor file web.xml because a Java servlet can be mapped to URL via XML like this: You can fix by either correcting the URL or correcting the URL mapping in the annotation. If the request URL is /view_books the server will raise HTTP 404 error. For example: class ViewBookServlet extends HttpServlet This servlet handles the URL /view_book. The URL is not handled by any Java servletsYou need to check URL mapping in your servlet classes to make sure the requested URL is actually handled by a servlet. However, sometimes it’s not easy like that, making it is an annoying error.Here I suggest some possible reasons and how to fix the error HTTP 404 in Java web development with Tomcat. Most of the time, you can fix this error by correcting the URL. The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.This error means the server could not find the requested resource (JSP, HTML, images…) and returns HTTP status code 404. In Java web development with Tomcat, it’s very often that you get HTTP 404 error like this: The error code is HTTP 404 (not found) and the description is: